Introduction to labelled

Joseph Larmarange

The purpose of the labelled package is to provide functions to manipulate metadata as variable labels, value labels and defined missing values using the haven_labelled and haven_labelled_spss classes introduced in haven package.

These classes allow to add metadata (variable, value labels and SPSS-style missing values) to vectors.

It should be noted that value labels doesn’t imply that your vectors should be considered as categorical or continuous. Therefore, value labels are not intended to be use for data analysis. For example, before performing modeling, you should convert vectors with value labels into factors or into classic numeric/character vectors.

Therefore, two main approaches could be considered.

Two main approaches

In approach A, haven_labelled vectors are converted into factors or into numeric/character vectors just after data import, using unlabelled(), to_factor() or unclass(). Then, data cleaning, recoding and analysis are performed using classic R vector types.

In approach B, haven_labelled vectors are kept for data cleaning and coding, allowing to preserved original recoding, in particular if data should be reexported after that step. Functions provided by labelled will be useful for managing value labels. However, as in approach A, haven_labelled vectors will have to be converted into classic factors or numeric vectors before data analysis (in particular modeling) as this is the way categorical and continuous variables should be coded for analysis functions.

Variable labels

A variable label could be specified for any vector using var_label.

library(labelled)

var_label(iris$Sepal.Length) <- "Length of sepal"

It’s possible to add a variable label to several columns of a data frame using a named list.

var_label(iris) <- list(Petal.Length = "Length of petal", Petal.Width = "Width of Petal")

To get the variable label, simply call var_label.

var_label(iris$Petal.Width)
## [1] "Width of Petal"
var_label(iris)
## $Sepal.Length
## [1] "Length of sepal"
## 
## $Sepal.Width
## NULL
## 
## $Petal.Length
## [1] "Length of petal"
## 
## $Petal.Width
## [1] "Width of Petal"
## 
## $Species
## NULL

To remove a variable label, use NULL.

var_label(iris$Sepal.Length) <- NULL

In RStudio, variable labels will be displayed in data viewer.

View(iris)

You can display and search through variable names and labels with look_for():

look_for(iris)
##  pos variable     label           col_type values    
##  1   Sepal.Length —               dbl                
##  2   Sepal.Width  —               dbl                
##  3   Petal.Length Length of petal dbl                
##  4   Petal.Width  Width of Petal  dbl                
##  5   Species      —               fct      setosa    
##                                            versicolor
##                                            virginica
look_for(iris, "pet")
##  pos variable     label           col_type values
##  3   Petal.Length Length of petal dbl            
##  4   Petal.Width  Width of Petal  dbl
look_for(iris, details = FALSE)
##  pos variable     label          
##  1   Sepal.Length —              
##  2   Sepal.Width  —              
##  3   Petal.Length Length of petal
##  4   Petal.Width  Width of Petal 
##  5   Species      —

Value labels

The first way to create a labelled vector is to use the labelled function. It’s not mandatory to provide a label for each value observed in your vector. You can also provide a label for values not observed.

v <- labelled(c(1,2,2,2,3,9,1,3,2,NA), c(yes = 1, no = 3, "don't know" = 8, refused = 9))
v
## <labelled<double>[10]>
##  [1]  1  2  2  2  3  9  1  3  2 NA
## 
## Labels:
##  value      label
##      1        yes
##      3         no
##      8 don't know
##      9    refused

Use val_labels to get all value labels and val_label to get the value label associated with a specific value.

val_labels(v)
##        yes         no don't know    refused 
##          1          3          8          9
val_label(v, 8)
## [1] "don't know"

val_labels could also be used to modify all the value labels attached to a vector, while val_label will update only one specific value label.

val_labels(v) <- c(yes = 1, nno = 3, bug = 5)
v
## <labelled<double>[10]>
##  [1]  1  2  2  2  3  9  1  3  2 NA
## 
## Labels:
##  value label
##      1   yes
##      3   nno
##      5   bug
val_label(v, 3) <- "no"
v
## <labelled<double>[10]>
##  [1]  1  2  2  2  3  9  1  3  2 NA
## 
## Labels:
##  value label
##      1   yes
##      3    no
##      5   bug

With val_label, you can also add or remove specific value labels.

val_label(v, 2) <- "maybe"
val_label(v, 5) <- NULL
v
## <labelled<double>[10]>
##  [1]  1  2  2  2  3  9  1  3  2 NA
## 
## Labels:
##  value label
##      1   yes
##      3    no
##      2 maybe

To remove all value labels, use val_labels and NULL. The labelled class will also be removed.

val_labels(v) <- NULL
v
##  [1]  1  2  2  2  3  9  1  3  2 NA

Adding a value label to a non labelled vector will apply labelled class to it.

val_label(v, 1) <- "yes"
v
## <labelled<double>[10]>
##  [1]  1  2  2  2  3  9  1  3  2 NA
## 
## Labels:
##  value label
##      1   yes

Note that applying val_labels to a factor will have no effect!

f <- factor(1:3)
f
## [1] 1 2 3
## Levels: 1 2 3
val_labels(f) <- c(yes = 1, no = 3)
f
## [1] 1 2 3
## Levels: 1 2 3

You could also apply value labels to several columns of a data frame.

df <- data.frame(v1 = 1:3, v2 = c(2, 3, 1), v3 = 3:1)

val_label(df, 1) <- "yes"
val_label(df[, c("v1", "v3")], 2) <- "maybe"
val_label(df[, c("v2", "v3")], 3) <- "no"
val_labels(df)
## $v1
##   yes maybe 
##     1     2 
## 
## $v2
## yes  no 
##   1   3 
## 
## $v3
##   yes maybe    no 
##     1     2     3
val_labels(df[, c("v1", "v3")]) <- c(YES = 1, MAYBE = 2, NO = 3)
val_labels(df)
## $v1
##   YES MAYBE    NO 
##     1     2     3 
## 
## $v2
## yes  no 
##   1   3 
## 
## $v3
##   YES MAYBE    NO 
##     1     2     3
val_labels(df) <- NULL
val_labels(df)
## $v1
## NULL
## 
## $v2
## NULL
## 
## $v3
## NULL
val_labels(df) <- list(v1 = c(yes = 1, no = 3), v2 = c(a = 1, b = 2, c = 3))
val_labels(df)
## $v1
## yes  no 
##   1   3 
## 
## $v2
## a b c 
## 1 2 3 
## 
## $v3
## NULL

Sorting value labels

Value labels are sorted by default in the order they have been created.

v <- c(1,2,2,2,3,9,1,3,2,NA)
val_label(v, 1) <- "yes"
val_label(v, 3) <- "no"
val_label(v, 9) <- "refused"
val_label(v, 2) <- "maybe"
val_label(v, 8) <- "don't know"
v
## <labelled<double>[10]>
##  [1]  1  2  2  2  3  9  1  3  2 NA
## 
## Labels:
##  value      label
##      1        yes
##      3         no
##      9    refused
##      2      maybe
##      8 don't know

It could be useful to reorder the value labels according to their attached values.

sort_val_labels(v)
## <labelled<double>[10]>
##  [1]  1  2  2  2  3  9  1  3  2 NA
## 
## Labels:
##  value      label
##      1        yes
##      2      maybe
##      3         no
##      8 don't know
##      9    refused
sort_val_labels(v, decreasing = TRUE)
## <labelled<double>[10]>
##  [1]  1  2  2  2  3  9  1  3  2 NA
## 
## Labels:
##  value      label
##      9    refused
##      8 don't know
##      3         no
##      2      maybe
##      1        yes

If you prefer, you can also sort them according to the labels.

sort_val_labels(v, according_to = "l")
## <labelled<double>[10]>
##  [1]  1  2  2  2  3  9  1  3  2 NA
## 
## Labels:
##  value      label
##      8 don't know
##      2      maybe
##      3         no
##      9    refused
##      1        yes

User defined missing values (SPSS’s style)

haven (>= 2.0.0) introduced an additional haven_labelled_spss class to deal with user defined missing values. In such case, additional attributes will be used to indicate with values should be considered as missing, but such values will not be stored as internal NA values. You should note that most R function will not take this information into account. Therefore, you will have to convert missing values into NA if required before analysis. These defined missing values could co-exist with internal NA values.

It is possible to manipulate this missing values with na_values() and na_range(). Note that is.na() will return TRUE as well for user-defined missing values.

v <- labelled(c(1,2,2,2,3,9,1,3,2,NA), c(yes = 1, no = 3, "don't know" = 9))
v
## <labelled<double>[10]>
##  [1]  1  2  2  2  3  9  1  3  2 NA
## 
## Labels:
##  value      label
##      1        yes
##      3         no
##      9 don't know
na_values(v) <- 9
na_values(v)
## [1] 9
v
## <labelled_spss<double>[10]>
##  [1]  1  2  2  2  3  9  1  3  2 NA
## Missing values: 9
## 
## Labels:
##  value      label
##      1        yes
##      3         no
##      9 don't know
is.na(v)
##  [1] FALSE FALSE FALSE FALSE FALSE  TRUE FALSE FALSE FALSE  TRUE
na_values(v) <- NULL
v
## <labelled<double>[10]>
##  [1]  1  2  2  2  3  9  1  3  2 NA
## 
## Labels:
##  value      label
##      1        yes
##      3         no
##      9 don't know
na_range(v) <- c(5, Inf)
na_range(v)
## [1]   5 Inf
v
## <labelled_spss<double>[10]>
##  [1]  1  2  2  2  3  9  1  3  2 NA
## Missing range:  [5, Inf]
## 
## Labels:
##  value      label
##      1        yes
##      3         no
##      9 don't know

Since version 2.1.0, it is not mandatory to define at least one value label before defining missing values.

x <- c(1, 2, 2, 9)
na_values(x) <- 9
x
## <labelled_spss<double>[4]>
## [1] 1 2 2 9
## Missing values: 9

To convert user defined missing values into NA, simply use user_na_to_na().

v <- labelled_spss(1:10, c(Good = 1, Bad = 8), na_values = c(9, 10))
v
## <labelled_spss<integer>[10]>
##  [1]  1  2  3  4  5  6  7  8  9 10
## Missing values: 9, 10
## 
## Labels:
##  value label
##      1  Good
##      8   Bad
v2 <- user_na_to_na(v)
v2
## <labelled<integer>[10]>
##  [1]  1  2  3  4  5  6  7  8 NA NA
## 
## Labels:
##  value label
##      1  Good
##      8   Bad

You can also remove user missing values definition without converting these values to NA.

v <- labelled_spss(1:10, c(Good = 1, Bad = 8), na_values = c(9, 10))
v
## <labelled_spss<integer>[10]>
##  [1]  1  2  3  4  5  6  7  8  9 10
## Missing values: 9, 10
## 
## Labels:
##  value label
##      1  Good
##      8   Bad
v2 <- remove_user_na(v)
## Some user defined missing values have been removed but not converted to NA.
v2
## <labelled<integer>[10]>
##  [1]  1  2  3  4  5  6  7  8  9 10
## 
## Labels:
##  value label
##      1  Good
##      8   Bad

or

v <- labelled_spss(1:10, c(Good = 1, Bad = 8), na_values = c(9, 10))
v
## <labelled_spss<integer>[10]>
##  [1]  1  2  3  4  5  6  7  8  9 10
## Missing values: 9, 10
## 
## Labels:
##  value label
##      1  Good
##      8   Bad
na_values(v) <- NULL
v
## <labelled<integer>[10]>
##  [1]  1  2  3  4  5  6  7  8  9 10
## 
## Labels:
##  value label
##      1  Good
##      8   Bad

Other conversion to NA

In some cases, values who don’t have an attached value label could be considered as missing. nolabel_to_na will convert them to NA.

v <- labelled(c(1,2,2,2,3,9,1,3,2,NA), c(yes = 1, maybe = 2, no = 3))
v
## <labelled<double>[10]>
##  [1]  1  2  2  2  3  9  1  3  2 NA
## 
## Labels:
##  value label
##      1   yes
##      2 maybe
##      3    no
nolabel_to_na(v)
## <labelled<double>[10]>
##  [1]  1  2  2  2  3 NA  1  3  2 NA
## 
## Labels:
##  value label
##      1   yes
##      2 maybe
##      3    no

In other cases, a value label is attached only to specific values that corresponds to a missing value. For example:

size <- labelled(c(1.88, 1.62, 1.78, 99, 1.91), c("not measured" = 99))
size
## <labelled<double>[5]>
## [1]  1.88  1.62  1.78 99.00  1.91
## 
## Labels:
##  value        label
##     99 not measured

In such cases, val_labels_to_na could be appropriate.

val_labels_to_na(size)
## [1] 1.88 1.62 1.78   NA 1.91

These two functions could also be applied to an overall data frame. Only labelled vectors will be impacted.

Converting to factor

A labelled vector could easily be converted to a factor with to_factor.

v <- labelled(c(1,2,2,2,3,9,1,3,2,NA), c(yes = 1, no = 3, "don't know" = 8, refused = 9))
v
## <labelled<double>[10]>
##  [1]  1  2  2  2  3  9  1  3  2 NA
## 
## Labels:
##  value      label
##      1        yes
##      3         no
##      8 don't know
##      9    refused
to_factor(v)
##  [1] yes     2       2       2       no      refused yes     no      2      
## [10] <NA>   
## Levels: yes 2 no don't know refused

The levels argument allows to specify what should be used as the factor levels, i.e. the labels (default), the values or the labels prefixed with values.

to_factor(v, levels = "v")
##  [1] 1    2    2    2    3    9    1    3    2    <NA>
## Levels: 1 2 3 8 9
to_factor(v, levels = "p")
##  [1] [1] yes     [2] 2       [2] 2       [2] 2       [3] no      [9] refused
##  [7] [1] yes     [3] no      [2] 2       <NA>       
## Levels: [1] yes [2] 2 [3] no [8] don't know [9] refused

The ordered argument will create an ordinal factor.

to_factor(v, ordered = TRUE)
##  [1] yes     2       2       2       no      refused yes     no      2      
## [10] <NA>   
## Levels: yes < 2 < no < don't know < refused

The argument nolabel_to_na specify if the corresponding function should be applied before converting to a factor. Therefore, the two following commands are equivalent.

to_factor(v, nolabel_to_na = TRUE)
##  [1] yes     <NA>    <NA>    <NA>    no      refused yes     no      <NA>   
## [10] <NA>   
## Levels: yes no don't know refused
to_factor(nolabel_to_na(v))
##  [1] yes     <NA>    <NA>    <NA>    no      refused yes     no      <NA>   
## [10] <NA>   
## Levels: yes no don't know refused

sort_levels specifies how the levels should be sorted: "none" to keep the order in which value labels have been defined, "values" to order the levels according to the values and "labels" according to the labels. "auto" (default) will be equivalent to "none" except if some values with no attached labels are found and are not dropped. In that case, "values" will be used.

to_factor(v, sort_levels = "n")
##  [1] yes     2       2       2       no      refused yes     no      2      
## [10] <NA>   
## Levels: yes no don't know refused 2
to_factor(v, sort_levels = "v")
##  [1] yes     2       2       2       no      refused yes     no      2      
## [10] <NA>   
## Levels: yes 2 no don't know refused
to_factor(v, sort_levels = "l")
##  [1] yes     2       2       2       no      refused yes     no      2      
## [10] <NA>   
## Levels: 2 don't know no refused yes

The function to_labelled could be used to turn a factor into a labelled numeric vector.

f <- factor(1:3, labels = c("a", "b", "c"))
to_labelled(f)
## <labelled<double>[3]>
## [1] 1 2 3
## 
## Labels:
##  value label
##      1     a
##      2     b
##      3     c

Note that to_labelled(to_factor(v)) will not be equal to v due to the way factors are stored internally by R.

v
## <labelled<double>[10]>
##  [1]  1  2  2  2  3  9  1  3  2 NA
## 
## Labels:
##  value      label
##      1        yes
##      3         no
##      8 don't know
##      9    refused
to_labelled(to_factor(v))
## <labelled<double>[10]>
##  [1]  1  2  2  2  3  5  1  3  2 NA
## 
## Labels:
##  value      label
##      1        yes
##      2          2
##      3         no
##      4 don't know
##      5    refused

Other type of conversions

You can use to_character() for converting into a character vector instead of a factor.

v
## <labelled<double>[10]>
##  [1]  1  2  2  2  3  9  1  3  2 NA
## 
## Labels:
##  value      label
##      1        yes
##      3         no
##      8 don't know
##      9    refused
to_character(v)
##  [1] "yes"     "2"       "2"       "2"       "no"      "refused" "yes"    
##  [8] "no"      "2"       NA

To remove the haven_class, you can simply use unclass().

unclass(v)
##  [1]  1  2  2  2  3  9  1  3  2 NA
## attr(,"labels")
##        yes         no don't know    refused 
##          1          3          8          9

Note that value labels will be preserved as an attribute to the vector.

remove_val_labels(v)
##  [1]  1  2  2  2  3  9  1  3  2 NA

To remove value labels, use remove_val_labels().

remove_val_labels(v)
##  [1]  1  2  2  2  3  9  1  3  2 NA

Note that if your vector does have user-defined missing values, you may also want to use remove_user_na().

x <- c(1, 2, 2, 9)
na_values(x) <- 9
val_labels(x) <- c(yes = 1, no = 2)
var_label(x) <- "A test variable"
x
## <labelled_spss<double>[4]>: A test variable
## [1] 1 2 2 9
## Missing values: 9
## 
## Labels:
##  value label
##      1   yes
##      2    no
remove_val_labels(x)
## <labelled_spss<double>[4]>: A test variable
## [1] 1 2 2 9
## Missing values: 9
remove_user_na(x)
## Some user defined missing values have been removed but not converted to NA.
## <labelled<double>[4]>: A test variable
## [1] 1 2 2 9
## 
## Labels:
##  value label
##      1   yes
##      2    no
remove_user_na(x, user_na_to_na = TRUE)
## <labelled<double>[4]>: A test variable
## [1]  1  2  2 NA
## 
## Labels:
##  value label
##      1   yes
##      2    no
remove_val_labels(remove_user_na(x))
## Some user defined missing values have been removed but not converted to NA.
## [1] 1 2 2 9
## attr(,"label")
## [1] "A test variable"
unclass(x)
## [1] 1 2 2 9
## attr(,"labels")
## yes  no 
##   1   2 
## attr(,"na_values")
## [1] 9
## attr(,"label")
## [1] "A test variable"

You can remove all labels and user-defined missing values with remove_labels(). Use keep_var_label = TRUE to preserve only variable label.

remove_labels(x, user_na_to_na = TRUE)
## [1]  1  2  2 NA
remove_labels(x, user_na_to_na = TRUE, keep_var_label = TRUE)
## [1]  1  2  2 NA
## attr(,"label")
## [1] "A test variable"

Conditional conversion to factors

For any analysis, it is the responsibility of user to identify which labelled numeric vectors should be considered as categorical (and therefore converted into factors using to_factor()) and which variables should be treated as continuous (and therefore unclassed into numeric using base::unclass()).

It should be noted that most functions expect categorical variables to be coded as factors. It includes most modeling functions (such as stats::lm() or stats::glm()) or plotting functions from ggplot2.

In most of cases, if data documentation was properly done, categorical variables corresponds to vectors where all observed values have a value label while vectors where only few values have a value label should be considered as continuous.

In that situation, you could apply the unlabelled() method to an overall data frame. By default, unlabelled() works as follow:

df <- data.frame(
  a = labelled(c(1, 1, 2, 3), labels = c(No = 1, Yes = 2)),
  b = labelled(c(1, 1, 2, 3), labels = c(No = 1, Yes = 2, DK = 3)),
  c = labelled(c(1, 1, 2, 2), labels = c(No = 1, Yes = 2, DK = 3)),
  d = labelled(c("a", "a", "b", "c"), labels = c(No = "a", Yes = "b")),
  e = labelled_spss(
    c(1, 9, 1, 2), 
    labels = c(No = 1, Yes = 2),
    na_values = 9
    )
)
df %>% look_for()
##  pos variable label col_type values 
##  1   a        —     dbl+lbl  [1] No 
##                              [2] Yes
##  2   b        —     dbl+lbl  [1] No 
##                              [2] Yes
##                              [3] DK 
##  3   c        —     dbl+lbl  [1] No 
##                              [2] Yes
##                              [3] DK 
##  4   d        —     chr+lbl  [a] No 
##                              [b] Yes
##  5   e        —     dbl+lbl  [1] No 
##                              [2] Yes
unlabelled(df)%>% look_for()
##  pos variable label col_type values
##  1   a        —     dbl            
##  2   b        —     fct      No    
##                              Yes   
##                              DK    
##  3   c        —     fct      No    
##                              Yes   
##                              DK    
##  4   d        —     chr            
##  5   e        —     fct      No    
##                              Yes
unlabelled(df, user_na_to_na = TRUE) %>% look_for()
##  pos variable label col_type values
##  1   a        —     dbl            
##  2   b        —     fct      No    
##                              Yes   
##                              DK    
##  3   c        —     fct      No    
##                              Yes   
##                              DK    
##  4   d        —     chr            
##  5   e        —     fct      No    
##                              Yes
unlabelled(df, drop_unused_labels = TRUE) %>% look_for()
##  pos variable label col_type values
##  1   a        —     dbl            
##  2   b        —     fct      No    
##                              Yes   
##                              DK    
##  3   c        —     fct      No    
##                              Yes   
##  4   d        —     chr            
##  5   e        —     fct      No    
##                              Yes

Importing labelled data

In haven package, read_spss, read_stata and read_sas are natively importing data using the labelled class and the label attribute for variable labels.

Functions from foreign package could also import some metadata from SPSS and Stata files. to_labelled can convert data imported with foreign into a labelled data frame. However, there are some limitations compared to using haven:

The memisc package provide functions to import variable metadata and store them in specific object of class data.set. The to_labelled method can convert a data.set into a labelled data frame.

  # from foreign
  library(foreign)
  df <- to_labelled(read.spss(
    "file.sav",
    to.data.frame = FALSE,
    use.value.labels = FALSE,
    use.missings = FALSE
 ))
 df <- to_labelled(read.dta(
   "file.dta",
   convert.factors = FALSE
 ))

 # from memisc
 library(memisc)
 nes1948.por <- UnZip("anes/NES1948.ZIP", "NES1948.POR", package="memisc")
 nes1948 <- spss.portable.file(nes1948.por)
 df <- to_labelled(nes1948)
 ds <- as.data.set(nes19480)
 df <- to_labelled(ds)

Using labelled with dplyr/magrittr

If you are using the %>% operator, you can use the functions set_variable_labels, set_value_labels, add_value_labels and remove_value_labels.

library(dplyr)
## 
## Attaching package: 'dplyr'
## The following objects are masked from 'package:stats':
## 
##     filter, lag
## The following objects are masked from 'package:base':
## 
##     intersect, setdiff, setequal, union
df <- data_frame(s1 = c("M", "M", "F"), s2 = c(1, 1, 2)) %>% 
  set_variable_labels(s1 = "Sex", s2 = "Question") %>%
  set_value_labels(s1 = c(Male = "M", Female = "F"), s2 = c(Yes = 1, No = 2))
## Warning: `data_frame()` was deprecated in tibble 1.1.0.
## Please use `tibble()` instead.
df$s2
## <labelled<double>[3]>: Question
## [1] 1 1 2
## 
## Labels:
##  value label
##      1   Yes
##      2    No

set_value_labels will replace the list of value labels while add_value_labels will update it.

df <- df %>%
  set_value_labels(s2 = c(Yes = 1, "Don't know" = 8, Unknown = 9))
df$s2
## <labelled<double>[3]>: Question
## [1] 1 1 2
## 
## Labels:
##  value      label
##      1        Yes
##      8 Don't know
##      9    Unknown
df <- df %>%
  add_value_labels(s2 = c(No = 2))
df$s2
## <labelled<double>[3]>: Question
## [1] 1 1 2
## 
## Labels:
##  value      label
##      1        Yes
##      8 Don't know
##      9    Unknown
##      2         No

You can also remove some variable and/or value labels.

df <- df %>%
  set_variable_labels(s1 = NULL)

# removing one value label
df <- df %>%
  remove_value_labels(s2 = 2)
df$s2
## <labelled<double>[3]>: Question
## [1] 1 1 2
## 
## Labels:
##  value      label
##      1        Yes
##      8 Don't know
##      9    Unknown
# removing several value labels
df <- df %>%
  remove_value_labels(s2 = 8:9)
df$s2
## <labelled<double>[3]>: Question
## [1] 1 1 2
## 
## Labels:
##  value label
##      1   Yes
# removing all value labels
df <- df %>%
  set_value_labels(s2 = NULL)
df$s2
## [1] 1 1 2
## attr(,"label")
## [1] "Question"

To convert variables, the easiest is to use unlabelled().

library(questionr)
data(fertility)
glimpse(women)
## Rows: 2,000
## Columns: 17
## $ id_woman          <dbl> 391, 1643, 85, 881, 1981, 1072, 1978, 1607, 738, 165~
## $ id_household      <dbl> 381, 1515, 85, 844, 1797, 1015, 1794, 1486, 711, 152~
## $ weight            <dbl> 1.803150, 1.803150, 1.803150, 1.803150, 1.803150, 0.~
## $ interview_date    <date> 2012-05-05, 2012-01-23, 2012-01-21, 2012-01-06, 201~
## $ date_of_birth     <date> 1997-03-07, 1982-01-06, 1979-01-01, 1968-03-29, 198~
## $ age               <dbl> 15, 30, 33, 43, 25, 18, 45, 23, 49, 31, 26, 45, 25, ~
## $ residency         <dbl+lbl> 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, ~
## $ region            <dbl+lbl> 4, 4, 4, 4, 4, 3, 3, 3, 3, 3, 3, 3, 2, 2, 2, 2, ~
## $ instruction       <dbl+lbl> 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 1, 1, 2, 1, 0, ~
## $ employed          <dbl+lbl> 1, 1, 0, 1, 1, 0, 1, 0, 1, 1, 1, 1, 1, 1, 1, 1, ~
## $ matri             <dbl+lbl> 0, 2, 2, 2, 1, 0, 1, 1, 2, 5, 2, 3, 0, 2, 1, 2, ~
## $ religion          <dbl+lbl> 1, 3, 2, 3, 2, 2, 3, 1, 3, 3, 2, 3, 2, 2, 2, 2, ~
## $ newspaper         <dbl+lbl> 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, ~
## $ radio             <dbl+lbl> 0, 1, 1, 0, 0, 1, 1, 0, 0, 0, 1, 1, 1, 1, 1, 0, ~
## $ tv                <dbl+lbl> 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 1, 1, 0, 0, 0, 0, ~
## $ ideal_nb_children <dbl+lbl>  4,  4,  4,  4,  4,  5, 10,  5,  4,  5,  6, 10, ~
## $ test              <dbl+lbl> 0, 9, 0, 0, 1, 0, 0, 0, 0, 1, 1, 0, 0, 1, 1, 0, ~
glimpse(women %>% unlabelled())
## Rows: 2,000
## Columns: 17
## $ id_woman          <dbl> 391, 1643, 85, 881, 1981, 1072, 1978, 1607, 738, 165~
## $ id_household      <dbl> 381, 1515, 85, 844, 1797, 1015, 1794, 1486, 711, 152~
## $ weight            <dbl> 1.803150, 1.803150, 1.803150, 1.803150, 1.803150, 0.~
## $ interview_date    <date> 2012-05-05, 2012-01-23, 2012-01-21, 2012-01-06, 201~
## $ date_of_birth     <date> 1997-03-07, 1982-01-06, 1979-01-01, 1968-03-29, 198~
## $ age               <dbl> 15, 30, 33, 43, 25, 18, 45, 23, 49, 31, 26, 45, 25, ~
## $ residency         <fct> rural, rural, rural, rural, rural, rural, rural, rur~
## $ region            <fct> West, West, West, West, West, South, South, South, S~
## $ instruction       <fct> none, none, none, none, primary, none, none, none, n~
## $ employed          <fct> yes, yes, no, yes, yes, no, yes, no, yes, yes, yes, ~
## $ matri             <fct> single, living together, living together, living tog~
## $ religion          <fct> Muslim, Protestant, Christian, Protestant, Christian~
## $ newspaper         <fct> no, no, no, no, no, no, no, no, no, no, no, no, no, ~
## $ radio             <fct> no, yes, yes, no, no, yes, yes, no, no, no, yes, yes~
## $ tv                <fct> no, no, no, no, no, yes, no, no, no, no, yes, yes, n~
## $ ideal_nb_children <dbl> 4, 4, 4, 4, 4, 5, 10, 5, 4, 5, 6, 10, 2, 6, 6, 6, 4,~
## $ test              <fct> no, missing, no, no, yes, no, no, no, no, yes, yes, ~

Alternatively, you can use functions as mutate_if or mutate_at. See the example below.

glimpse(to_factor(women))
## Rows: 2,000
## Columns: 17
## $ id_woman          <dbl> 391, 1643, 85, 881, 1981, 1072, 1978, 1607, 738, 165~
## $ id_household      <dbl> 381, 1515, 85, 844, 1797, 1015, 1794, 1486, 711, 152~
## $ weight            <dbl> 1.803150, 1.803150, 1.803150, 1.803150, 1.803150, 0.~
## $ interview_date    <date> 2012-05-05, 2012-01-23, 2012-01-21, 2012-01-06, 201~
## $ date_of_birth     <date> 1997-03-07, 1982-01-06, 1979-01-01, 1968-03-29, 198~
## $ age               <dbl> 15, 30, 33, 43, 25, 18, 45, 23, 49, 31, 26, 45, 25, ~
## $ residency         <fct> rural, rural, rural, rural, rural, rural, rural, rur~
## $ region            <fct> West, West, West, West, West, South, South, South, S~
## $ instruction       <fct> none, none, none, none, primary, none, none, none, n~
## $ employed          <fct> yes, yes, no, yes, yes, no, yes, no, yes, yes, yes, ~
## $ matri             <fct> single, living together, living together, living tog~
## $ religion          <fct> Muslim, Protestant, Christian, Protestant, Christian~
## $ newspaper         <fct> no, no, no, no, no, no, no, no, no, no, no, no, no, ~
## $ radio             <fct> no, yes, yes, no, no, yes, yes, no, no, no, yes, yes~
## $ tv                <fct> no, no, no, no, no, yes, no, no, no, no, yes, yes, n~
## $ ideal_nb_children <fct> 4, 4, 4, 4, 4, 5, 10, 5, 4, 5, 6, 10, 2, 6, 6, 6, 4,~
## $ test              <fct> no, missing, no, no, yes, no, no, no, no, yes, yes, ~
glimpse(women %>% mutate_if(is.labelled, to_factor))
## Rows: 2,000
## Columns: 17
## $ id_woman          <dbl> 391, 1643, 85, 881, 1981, 1072, 1978, 1607, 738, 165~
## $ id_household      <dbl> 381, 1515, 85, 844, 1797, 1015, 1794, 1486, 711, 152~
## $ weight            <dbl> 1.803150, 1.803150, 1.803150, 1.803150, 1.803150, 0.~
## $ interview_date    <date> 2012-05-05, 2012-01-23, 2012-01-21, 2012-01-06, 201~
## $ date_of_birth     <date> 1997-03-07, 1982-01-06, 1979-01-01, 1968-03-29, 198~
## $ age               <dbl> 15, 30, 33, 43, 25, 18, 45, 23, 49, 31, 26, 45, 25, ~
## $ residency         <fct> rural, rural, rural, rural, rural, rural, rural, rur~
## $ region            <fct> West, West, West, West, West, South, South, South, S~
## $ instruction       <fct> none, none, none, none, primary, none, none, none, n~
## $ employed          <fct> yes, yes, no, yes, yes, no, yes, no, yes, yes, yes, ~
## $ matri             <fct> single, living together, living together, living tog~
## $ religion          <fct> Muslim, Protestant, Christian, Protestant, Christian~
## $ newspaper         <fct> no, no, no, no, no, no, no, no, no, no, no, no, no, ~
## $ radio             <fct> no, yes, yes, no, no, yes, yes, no, no, no, yes, yes~
## $ tv                <fct> no, no, no, no, no, yes, no, no, no, no, yes, yes, n~
## $ ideal_nb_children <fct> 4, 4, 4, 4, 4, 5, 10, 5, 4, 5, 6, 10, 2, 6, 6, 6, 4,~
## $ test              <fct> no, missing, no, no, yes, no, no, no, no, yes, yes, ~
glimpse(women %>% mutate_at(vars(employed:religion), to_factor))
## Rows: 2,000
## Columns: 17
## $ id_woman          <dbl> 391, 1643, 85, 881, 1981, 1072, 1978, 1607, 738, 165~
## $ id_household      <dbl> 381, 1515, 85, 844, 1797, 1015, 1794, 1486, 711, 152~
## $ weight            <dbl> 1.803150, 1.803150, 1.803150, 1.803150, 1.803150, 0.~
## $ interview_date    <date> 2012-05-05, 2012-01-23, 2012-01-21, 2012-01-06, 201~
## $ date_of_birth     <date> 1997-03-07, 1982-01-06, 1979-01-01, 1968-03-29, 198~
## $ age               <dbl> 15, 30, 33, 43, 25, 18, 45, 23, 49, 31, 26, 45, 25, ~
## $ residency         <dbl+lbl> 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, ~
## $ region            <dbl+lbl> 4, 4, 4, 4, 4, 3, 3, 3, 3, 3, 3, 3, 2, 2, 2, 2, ~
## $ instruction       <dbl+lbl> 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 1, 1, 2, 1, 0, ~
## $ employed          <fct> yes, yes, no, yes, yes, no, yes, no, yes, yes, yes, ~
## $ matri             <fct> single, living together, living together, living tog~
## $ religion          <fct> Muslim, Protestant, Christian, Protestant, Christian~
## $ newspaper         <dbl+lbl> 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, ~
## $ radio             <dbl+lbl> 0, 1, 1, 0, 0, 1, 1, 0, 0, 0, 1, 1, 1, 1, 1, 0, ~
## $ tv                <dbl+lbl> 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 1, 1, 0, 0, 0, 0, ~
## $ ideal_nb_children <dbl+lbl>  4,  4,  4,  4,  4,  5, 10,  5,  4,  5,  6, 10, ~
## $ test              <dbl+lbl> 0, 9, 0, 0, 1, 0, 0, 0, 0, 1, 1, 0, 0, 1, 1, 0, ~